Question

2 % items in a lot are defective. What is the probability that an item randomly selected from this lot is non-defective?

Answer 1

A = Event that an item is defective

∴ P(A) = 2 % = \(\frac{2}{100 }\)= 0.02

A’ = Event that an item is non-defective

∴ P(A’) = 1 – P(A) = 1 – 0.02 = 0.98