Question

A particle of mass 0.5 kg travels in a straight line with velocity v = ax^3/2, Where a = 5m^[(–1)/2] s^–1. The work done by the net force during its displacement from x = 0 to x = 2m is 

(A) 50 J 

(B) 45 J 

(C) 25 J 

(D) None of these

Answer 1

Correct option: (A) 50 J

Explanation:

V = ax^(3/2) 

V = 5x^(3/2) 

when  x = 0, V = V₁ = 0

when  x = 2, V₂ = 5(2)^(3/2) 

Workdone = (1/2)m(V₂² – V₁²) = Δ KE

= (1/2) × 0.5 (25 × 8 – 0)

= 50 J