Question

The equation of the chord of parabola y² = 8x. Which is bisected at the point (2, – 3) is 

(a) 3x + 4y – 1 = 0

(b) 4x + 3y + 1 = 0 

(c) 3x – 4y + 1 = 0

(d) 4x – 3y – 1 = 0   

Answer 1

The correct option (b) 4x + 3y + 1 = 0   

Explanation:

Parabola: y² = 8x ⇒ a = 2

Required equation is (– 3)y – 4(x + 2) = (– 3)2 – 8(2)

 ∴  – 3y – 4x – 8 = 9 – 16 

∴  4x + 3y + 1 = 0.