Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
342 views
in Chemistry by (81.0k points)
closed by

For the following electrochemical cell at 298 K,

Pt(s) | H2 (g, 1 bar) | H+ (aq, 1 M) || M4+ (aq), M2+ (aq) | Pt(s)

Ecell = 0.092 V when \(\frac{[{M^{2+}(aq)]}}{[M^{4+}(aq)]}\)

Given : \(E^0_{M^{4+}/M^{2+}}\) = 0.151 v ; 2.303 RT/F = 0.059 V

The value of x is 

(A) -2 

(B) -1 

(C) 1 

(D) 2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...