An expression of energy density is given by u = α/β sin(αx/kt), where α, β are constants, x is displacement, k is Boltzmann constant ​

Question

An expression of energy density is given by \(u = \frac \alpha\beta sin(\frac{\alpha x}{kt})\), where α, β are constants, x is displacement, k is Boltzmann constant and t is the temperature. The dimensions of β will be :

(A) [ML²T^-2θ^-1]

(B) [M⁰L²T^-2]

(C) [M⁰L⁰T⁰]

(D) [M⁰L²T⁰]

Answer 1

Correct option is (D) [M⁰L²T⁰]