Question

The lines ax + by + c = 0, where 3a + 2b + 4c = 0 are concurrent at the point

(a) [(1/2), (3/4)]

(b) (1, 3)

(c) (3, 1)

(d) [(3/4), (1/2)]

Answer 1

The correct option (d) [(3/4), (1/2)]   

Explanation:

lines: ax + by + c = 0

where 3a + 2b + 4c = 0.

as 3a + 2b + 4c = 0.

⇒ (3/4)a + (b/2) + c = 0

⇒ set of lines ax + by + c  = 0 passes through point [(3/4), (1/2)]

i.e. They are concurrent at [(3/4), (1/2)].