Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
10.1k views
in Physics by (76.5k points)

At what distance from the center of earth, the value of acceleration due to gravity g will be half that of the surfaces (R = Radius of earth) 

(A) 2R 

(B) R 

(C) 1.414 R 

(D) 0.414 R

1 Answer

+1 vote
by (66.1k points)
selected by
 
Best answer

Correct option: (C) 1.414 R

Explanation:

at height h,  g' = g[R / (R + h)]2 

(g/2) = g[R / (R + h)]2 

(1 / √2) = [R / (R + h)]

R + h = √2 R

h = R(√2 – 1)

h = 0.414 R

hence distance from centre = R + h

= R + 0.414 R = 1.414 R

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...