Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
179 views
in Physics by (80.9k points)
closed by

Two bodies, each of mass M, are kept fixed with a separation 2L. A particle of mass m is projected from the midpoint of the line joining their centers, perpendicular to the line. The gravitational constant is G. The correct statement(s) is (are) (A) The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is

(A) The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 4√(GM/L)

(B) The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 2√(GM/L) . 

(C) The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 2√(GM/L) 

(D) The energy of the mass m remains constant.

1 Answer

+1 vote
by (77.0k points)
selected by
 
Best answer

(B) The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 2√(GM/L) . 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...