Question

A spherical body of radius R consists of a fluid of constant density and is in equilibrium under its own gravity. If P(r) is the pressure at r(r < R), then the correct option(s) is(are)

(A) p(r = 0) = 0  

(B) \(\frac{p(r=3R/4)}{p(r=2R/3)}=\frac{63}{80}\)

(C) \(\frac{p(r=3R/5)}{p(r=2R/5)}=\frac{16}{21}\)

(D) \(\frac{p(r=R/2)}{p(r=R/3)}=\frac{20}{27}\)

Answer 1

(B) \(\frac{p(r=3R/4)}{p(r=2R/3)}=\frac{63}{80}\)

(C) \(\frac{p(r=3R/5)}{p(r=2R/5)}=\frac{16}{21}\)