Choose the correct option. Hint T= true F = False
I. In the second period atomic radii of Be is 90 pm, F is 64 pm, & that of Ne is 160 pm
II. Atomic radii decreases from Li to Ne
III. The increase in size of Ne is due to presence of vanderwaals force of attraction & presence of covalent bond
IV. In Ne there is absence of covalent bond therefore the radii is vanderwaals radii
V. The order of radii is Metallic > Covalent > Vanderwaals
(a) TTFTF
(b) TTTFF
(c) TFFTT
(d) TFFFT
