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Solution of (d2y/dx2) = log x is: 

(A) y = (1/2)x2 log x – (3/4)x2 + c1x + c2

(B) y = (1/2)x2 log x + (3/4)x2 + c1x + c2

(C) y = (1/2)x2 log x – (3/4)x2 – c1x + c2 

(D) None of these

1 Answer

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Best answer

The correct option (A) y = (1/2)x2 log x – (3/4)x2 + c1x + c2

Explanation:

(d2y/dx2) = log x 

∴ (dy/dx) = ∫log x ∙ dx 

(dy/dx) = x log x – x + c 

∴ y = ∫x log x dx – ∫x dx + ∫c ∙ dx 

Consider 

∫x ∙ log x dx = log x∫x dx – ∫(x2/2) × (1/x)dx 

= log x ∙ (x2/2) – (x2/4) 

∴ y = log x ∙ (x2/2) – (x2/4) – (x2/2) + cx + d 

= (1/2)x2 log x – (3/4)x2 + cx + d 

∴ y = (1/2)x2 log x – (3/4)x2 + c1x + c2

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