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nP3 = 990 हो, तो n का मूल्य ज्ञात करो ।

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nPr की परिभाषा के अनुसार

nP3 = n(n – 1) (n – 2)

∴ n (n – 1) (n – 2) = 990

अब हम विचार करेंगे की ऐसी कौन-सी तीन क्रमिक मूल्य है कि जिसका गुणाकार 990 होगा ? तो हल प्राप्त होगा ।

11 × 10 × 9 उसे निम्नस्वरूप में लिखेंगे ।

∴ n (n – 1) (n – 2) = 11 × 10 × 9

∴ n = 11 = 11 (11 – 1) (11 – 2)

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