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यदि Sn = 4 (3n – 1) हो, तो Tn + 1 ज्ञात करो ।

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हम जानते है कि Tn + 1 = Sn + 1 – Sn

Tn + 1 = 4 (3n + 1 – 1) – 4 (3n – 1)

= 4 (3n + 1 – 1 – 3n + 1) = 4 (3n + 1 – 3n)

= 4 (3n) (3 – 1) = 4 (3n) (2)

∴ Tn + 1 = 8 (3n)

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