Question

5.3 g of Na₂ CO₃ have been dissolved to make 250 mL of the solution. The normality of the resulting solution will be :

(a) 0.1 N

(b) 0.2 N

(c) 0.4 N

(d) 0.8 N

Answer 1

Correct option is  (c) 0.4 N

Answer 2

Correct option is (c) 0.4 N

 Equivalent wt of \(Na_2CO_3=\frac{106}{2}=53\)

\(\therefore\) Number of equivalent of \(Na_2CO_3=\frac{5.3}{53}=0.1\)

\(\therefore\) Normality of solution \(=\frac{0.1}{250}\times1000\)

\(=0.4N.\)