Correct option is (a) 67.2 L
\(2BCl_3 +3H_2\longrightarrow2B+6HCl\)
Number of moles of \(B=\frac{21.6}{10.8}=2\) mol.
\(\because\) 2 moles of B produced by 3 mol of Hydrogen.
\(\therefore\) volume of \(H_2\) at 273 k and 1 atm pressure.
PV = nRT
\(V=\frac{3\times0.082\times273}{1}\)
\(V=67.16\)
\(V=67.2\,L.\)