Question

500 mL of 0.25 M Na₂SO₄ is added to an aqueous solution of 15 g of BaCl₂ resulting in the formation of white precipitate of insoluble BaSO₄ . How many moles and how many grams of BaSO₄ are formed?

Answer 1

Reaction involved in the process is :

Molarity of Na₂ SO₄ is 0.25. Thus, 1000 mL solution contains 0.25 mole Na₂SO₄ .  Number of moles of Na₂SO₄ in 500 mL will be 0.125

1 mole Na₂SO₄ reacts with 1 mole BaCI

0.125 moles Na₂SO₄ will react with 0.125 moles BaSO₄

Required moles of BaCl₂ > available moles of BaCl₂

Thus BaCl₂ is limiting reactant. 1 mole BaCl₂ will give 1 mole Na₂SO₄

⇒0.0721 moles of BaCI₂ will give 0.0721 moles of BaSO₄