Question

Correct set of four quantum numbers for the valence (outermost) electron of rubidium (Z = 37) is

a. 5, 0, 0, +½

b. 5, 1, 0, +½

c. 5, 1, 1, +½

d. 6, 0, 0, +½

Answer 1

Correct option is a. 5, 0, 0, +½

Answer 2

Correct option is (a) \(5, 0, 0, +\frac12\) 

electric configuration of Rb(37) \(=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1\)

valence electron in 5s orbital.

\(\therefore\) Quantum number are- \(n = 5, l = 0, m = 0 ,s = +\frac12\).