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+1 vote
43.2k views
in Chemistry by (66.1k points)

The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 BM. The suitable ligand for this complex is : 

(1) NCS– 

(2) CN 

(3) ethylenediamine 

(4) CO

1 Answer

+2 votes
by (71.4k points)
selected by
 
Best answer

Correct option: (1) NCS

Explanation:

µ = 5.9 BM → 5 unpaired e 

Mn2+ –[Ar]3d5 configuration only possible with relatively weaker ligand. 

So NCS is the answer (1).

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