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If |(a-b-c,2a,2a),(2b, b-c-a,2b),(2c,2c, c-a-b)| = (a + b + c)(x + a + b + c)2, x ≠ 0 and a + b + c ≠ 0, then x is equal to :

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If |(a-b-c,2a,2a),(2b, b-c-a,2b),(2c,2c, c-a-b)| = (a + b + c)(x + a + b + c)2, x ≠ 0 and a + b + c ≠ 0, then x is equal to :

(1)   2(a + b + c) 

(2)  –2(a + b + c) 

(3)  abc

(4)  –(a + b + c)

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Correct option  (2)  –2(a + b + c)

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