The correct option is (d) as explained below:
The ray PQ incident normally on the face AB of the prism proceeds undeviated through the prism and strikes the face AC at the point R, as shown in the adjoining figure. From the right angled triangle AQR it is clear that angle QRA = 30º. Therefore, it follows that the angle of incidence QRN at the face AC is 60º. Since this is greater than the critical angle (which is slightly less than 42º for the material of refractive index 1.5), the ray is totally reflected along RS as shown in the figure.
[You may calculate the critical angle using the equation,
n = 1/sinC where n is the refractive index and C is the critical angle.
Therefore sinC = 1/1.5 = 0.66667 and C = sin–1(0.66667) = 41.8º]