Question

The equation of hyperbola whose foci are (8,3), (0,3) and eccentricity is 4/3 is

a. \(\frac{(x -4)^2}{9} - \frac{(y - 3)^2}{7} = 1\)

b. \(\frac{(x -4)^2}{7} - \frac{(y - 3)^2}{9} = 1\)

c. \(\frac{(x -3)^2}{9} - \frac{(y - 4)^2}{7} = 1\)

d. none of these

Answer 1

a. \(\frac{(x -4)^2}{9} - \frac{(y - 3)^2}{7} = 1\)