Question

A line cuts the x-axis at A(5, 0) and the y-axis at B(0, –3). A variable line PQ is drawn perpendicular to AB cutting the x-axis at P and the y-axis at Q. If AQ and BP meet at R, then the locus of R is 

(A) x² + y² – 5x + 3y = 0 

(B) x² + y² + 5x + 3y = 0 

(C) x² + y² + 5x – 3y = 0 

(D) x² + y² – 5x – 3y = 0

Answer 1

The correct option (A) x² + y² – 5x + 3y = 0

Explanation: