The value of x + y + z = 15. If a, x, y, z, b are in A.P, while the value of 1/x + 1/y + 1/z is 5/3. ​

Question

The value of x + y + z = 15. If a, x, y, z, b are in A.P, while the value of \(\frac1x + \frac1y + \frac1z \) is \(\frac 53\). If \(\frac1a,\frac1x , \frac1y , \frac1z ,\frac1b\) are in A.P, then

(a) a = 1, b = 9

(b) a = 9 , b = 1

(c) can not find

(d) None of these

Answer 1

Correct option is (a) a = 1, b = 9 & (b) a = 9 , b = 1