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A feasible cell was constructed by joining the two half cells below. Cu2+ (aq) + 2e- → Cu(s) Eo = - 0.76 V. What is the standard e.m.f. of the cell?

A. - 1.1V

B. - 0.42V

C. +0.42V

D. +1.1V

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1 Answer

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The correct option is (D) +1.1V.

e.m.f. = + 0.34 -(-0.76) 

= 0.34 + 0.76 

= +1.1V

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