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If x cosα + ysinα = 2a, xcosβ + ysinβ = 2a and 2sin α/2 sin β/2 = 1, then

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in Trigonometry by (53.7k points)

If x cosα + ysinα = 2a, xcosβ + ysinβ = 2a and 2sin α/2 sin β/2 = 1, then

(a) \(cos\alpha + cos\beta = \frac{2ax}{x^2+ y^2}\)

(b) \(cos\alpha \,cos\beta = \frac{2a^2 - y^2}{x^2+ y^2}\)

(c) y2 = 4a(a–x)

(d) cosα + cosβ = 2cosα cosβ

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Correct option is (c) y2 = 4a(a–x)

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