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in Trigonometry by (53.7k points)
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In △ABC sin4A + sin4B + sin4C = sin2B sin2C + 2sin2C sin2A + 2sin2A sin2B, then ∠A =

(a) \(\frac \pi 6, \frac{5\pi}6\)

(b) \(\frac \pi 6, \frac{5\pi}3\)

(c) \(\frac{5\pi}6, \frac \pi 3\)

(d) None of these

1 Answer

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by (53.4k points)
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Best answer

Correct option is (a) \(\frac \pi 6, \frac{5\pi}6\) 

Given equation is,

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