Potential decreases as we move from a weaker to a stronger electric field.
\(\vec{E_x}= - \dfrac{\partial V}{\partial x}\)
This relation can be interpreted graphically where E is the slope of a V-X curve, now coming back to the question.
from 0 to 2, the slope of the graph is positive and a constant, which indicates potential increase, this means electric field is constant and negative.
From 2 to 4, the potential is constant and the slope is zero, therefore electric field is zero
From 4 to 6, potential is decreasing and slope is constant, therefore electric field is positive and constant.
Option (i) is the correct answer
