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From first principle, find the derivative of 1/√2x+5.

\(f(x) = \frac1{\sqrt{2x +5}}\)

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\(f(x) = \frac1{\sqrt{2x +5}}\)

\(f(x+h) = \frac1{\sqrt{2(x+ h) +5}}\)

\(f'(x) = \lim\limits_{h\to 0} \frac{f(x+h)-f(x)}h\)

\(= \lim\limits_{h \to 0} \cfrac{\frac1{\sqrt{2(x+h)+5}}-\frac 1{\sqrt{2x+5}}}{h}\)

\(= \lim\limits_{h \to 0}\frac{\sqrt{2x+5} - \sqrt{2(x+h)+5}}{h\sqrt{2(x+h)+5}\sqrt{2x + 5}}\)

\(= \lim\limits_{h \to 0} \frac{(2x + 5) - (2x + 2h+5)}{h\left(\sqrt{2(x+h)+5} + \sqrt{2x+5}\right) \sqrt{2x +5}\sqrt{2x + 2h + 5}}\)

\(= \lim\limits_{h \to 0} \frac{-2}{2(2x + 5)^{3/2}}\)

\(= \frac{-1}{(2x + 5)^{3/2}}\)

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