(2) 22.5 volt
Let Rv be the resistance of the voltmeter. Then Rv and 400Ω resistance, when connected in parallel would have an equivalent resistances given by
and the current in the circuit with correspond to
According to question potential drop across AB is 30 volt so
Solving we obtain Rv = 1200Ω
Now when the voltmeter is connected across 300Ω the equivalent resistance of their parallel combination, is
Now the total resistance of the circuit would be (240+400)Ω = 640Ω and the corresponding current is (60/640)
Hence in this case reading of the voltmeter would be
60/640 x 240 = 22.5 Volt.