Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
97 views
in Physics by (51.8k points)
closed by

If we represent earth’s magnetic field at the equator, by B, the dipole moment of earth (radius = R)’s equivalent magnet is given by

(1) \(\frac{4\pi R^3 B}{μ_0}\) 

(2) \(\frac{4\pi R^2 B}{μ_0}\)

(3) \(\frac{2\pi RB^2}{μ_0}\)

(4) \(\frac{2\pi RB}{μ_0}\)

1 Answer

+1 vote
by (52.2k points)
selected by
 
Best answer

(1) \(\frac{4\pi R^3 B}{μ_0}\) 

We can assume earths magnetic field as due to a (short) bar magnet, centered at the centre of earth and held along its polar axis. 

We can then write:

where M is the dipole moment of earth’s equivalent magnet.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...