Question

Let δ₁ and δ₂ be the angle fo dip in any two vertical planes (other than the magnetic meridian) that are at right angles to each other. If, δ is the true value of the angle of dip, we would have

(1) tan² δ₁ + tan² δ₂ = tan²δ

(2) \(\frac{tan^2δ_1}{tan^2δ_2}=cot^2δ\)

(3) cot² δ₁ + cot² δ₂ = 1

(4) cot² δ = cot² δ₁ + cot² δ₂

Answer 1

(4) cot² δ = cot² δ₁ + cot² δ₂

Let the vertical plane, in which angle of dip is δ₁ subtends an angle θ with the magnetic meridian. Their other plane then subteneds an angle (π/2 - θ) with the magnetic meridian.