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A conducting rod of length L lies along the y–axis with one end at origin and the other end at (0, L, 0). There is a magnetic field B = B0y\(\hat{k}\) in that region. If the rod moves with a velocity V = V0\(\hat{i}\), the e.m.f induced between the ends of the rod will be

(1) \(\frac{B_0V_0L}{2}\)

(2) \(\frac{B_0V_0L^2}{2}\)

(3) B0V0 Ld

(4) \(\frac{B_0V_0L^2}{4}\)

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Best answer

 (2) \(\frac{B_0V_0L^2}{2}\)

The induced emf, across a small element dy of the rod is

∴ The induced emf across the rod of length L will be

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