Correct option: (A) √400 (m/s)
Explanation:
P = 3 atm
P = \(3\times 10^5\)
Pressure at the bottom P = \(\rho gh\)
\(3\times 10^5\) = \(\rho gh\)
Pressure due to liquid column.
\(P_1\) = \(3\times 10^5\) - \(1\times 10^5\)
\(P_1\) = \(2\times 10^5\,N/m^2\)
Velocity at water v = \(\sqrt{2gh} \)
\(\because \) P = \(\rho gh\)
h = \(\frac{P_1}{\rho g}\)
v = \(\sqrt{\frac{2g.P _1}{\rho g}}\)
v = \(\sqrt{\frac{2P _1}{\rho}}\)
v = \(\sqrt{\frac{2\times 2\times 10^5 }{10^3}}\)
v = \(\sqrt{4\times 10^2}\)
v = \(\sqrt{400}\,m/s\)