(1) K
Let B be the strength of the magnetic field between the poles of the horse shoes magnet. The magnetic flux, linked with the small coil, when it is present in the field region, is
ϕ = (Bπr2)n
The linked magnetic flux becomes zero when it is withdrawn from the field. The instantaneous induced emf, would be
ε = -dϕ/dt
The instantaneous induced current (k) is ε/R where R is the resistance of the coil-galvanometer circuit. The total charge flowing is given by
![](https://www.sarthaks.com/?qa=blob&qa_blobid=8481531628470199420)
Q, therefore, does not depend on Δt . This is shown in graph K.