Question

Calculate the volume of carbon iv oxide which will be produced by heating 80g of copper ii carbonate at room temperature.

Answer 1

\(CuCO_3 \xrightarrow{\triangle } CuO + CO_2\)

molar mass of CuCO₃ = 123.6 g

\(\therefore\) Number of moles of CuCO₃ = \(\frac{80}{123.6}\) = 0.65 g mol

\(\because\) 1 mole of CuCO₃ gives = 1 mol CO₂

\(\therefore\) 0.65 mol of CuCO₃ gives = 0.65 mol CO₂

\(\because\) As we know, At room temperature

One mole gas occupy = 22.4 L volume

\(\therefore\) Volume of 0.65 mol CO₂ = (22.4 x 0.65) L

= 14.56 L

Hence, On heating 80g CuCO₃ produce 14.56 L CO₂ gas at room temperature and at atmospheric pressure.