Centre and radius of circle x2 + y2 – 2x + 4y + 1 = 0 is (1,–2) and \(\sqrt{1 + 4-1}\) = 2 respectively.
If the distance of a line 3x – 4y = 1 from the centre (1,–2) is equal to radius then the line touches or it is tangent to a circle.

Let point of contact be (x1, y1) then equation of tangent to a circle x2 + y2 – 2x + 4y + 1 = 0 is

(1) and (2) are idenfical then comparing (1) and (2) we get
