Question

Tangent to the curve y = x² + 6 at a point (1, 7) touches the circle x² + y² + 16x + 12y + c = 0 at a point Q then coordinates of Q are

a. (–6, –11)

b. (–9, –13)

c. (–10, –15)

d. (–6, –7)

Answer 1

Correct option is d. (–6, –7)

Equation of tangent at (1, 7) to the curve y = x² + 6 is