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in Parabola by (51.4k points)
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Minimum area of circle which touches the parabola’s y2 = x2 + 1 and y2 = x + 1 is

a. \(\frac{9\pi}{32}\) sq. unit 

b. \(\frac{\pi}{4}\) sq. unit

c. \(\frac{7\pi}{32}\) sq. unit

d. \(\frac{9\pi}{16}\) sq. unit

1 Answer

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by (51.2k points)
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Best answer

Correct option is a. \(\frac{9\pi}{32}\) sq. unit

y = x+ 1 and y2 = x + 1 are symmetrical about y = x tangent at point. A and B are parallel to the line y = x

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