Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
193 views
in Physics by (51.8k points)
closed by

L1 is a convex lens of focal length 3f and L2 is a concave lens of focal length f. The two are placed a distance 2f apart. The principle axis of two lens are parallel, but a distance h apart, as shown in Fig. A parallel beam is incident on L1 . The emergent beam, after refraction at both L1 and L2 , is

(1) A parallel beam parallel to axis of L1 and L2

(2) A parallel beam, making an angle of tan-1 (h/y), in the anticlockwise direction, with the principal axis

(3) A parallel beam, making an angle of tan-1 (h/y) , in the clockwise direction, with the principle axis

(4) A divergent beam

1 Answer

+1 vote
by (52.2k points)
selected by
 
Best answer

(2) A parallel beam, making an angle of tan-1 (h/y), in the anticlockwise direction, with the principal axis

Fig shows the ray diagram. The incident parallel beam, after refraction at L1 would have meet its principle axis at point P. The point, P, acts as a virtual object for the concave lens, L2 , and is lying off the axis of L2 , in its focal plane. The emergent beam is, therefore, a parallel beam, inclined to the principle axis of L2 , at an angle θ . From right angled triangle O2 PF2 ;

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...