Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
574 views
in Physics by (51.8k points)
closed by

A glass plate, of refractive index 1.5, is coated with a thin layer of thickness t and refractive index μ1 = 1.8 . Light, of wave length λ , travelling in air is incident (nearly) normally an the layer. It is partly reflected at its upper and lower ends and the two reflected rays interfere. If λ = 648 nm, the minimum value of t, for which constructive interference would take place, is

(1) 45 nm

(2) 60 nm

(3) 90 nm

(4) 108 nm

1 Answer

+2 votes
by (52.2k points)
selected by
 
Best answer

(2) 60 nm

In Fig PQRS is the glass plate and PQQ1 P1 is the thin fim. AB is the (nearly normally) incident ray. BR is the reflected ray from the upper end and CD is the reflected ray at the lower and (P1Q1). DE is the corresponding emergent ray. Interference occurs between BR and DE. The path difference

Δ ≃ 2μ1t

There is an additional path difference of λ/2 due to reflection at PQ (reflection from the boundary of a denser medium). There is no extra path difference due to reflection at P1Q1 , as this reflection is from the boundary of a rarer medium. For constructive interference, we therefore, have

For minimum value of t, n = 1. Therefore

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...