First, let z1, z2, z3 be the affixes of the vertices A,B,C of an equilateral triangle ABC. Then, we have to prove that \(z_1^2 + z_2^2 + z_3^2 = z_1z_2 + z_2z_3 + z_3z_1\)
Since ΔABCis an equilateral triangle.
Therefore,
AB = BC = AC and ∠A = ∠B = ∠C = π/3.
Clearly, \(\vec{AC}\) can be obtained by rotating \(\vec {AB}\) in anticlockwise sense through 600.
\(\therefore\) z3 – z1 = (z2 – z1) eiπ/3 ......(1)
Also \(\vec {BC}\) can be obtained by rotating \(\vec {BA}\) by π/3 anticlockwise
