Question

For an isothermal expansion of a Perfect gas, the value of (ΔP / P) is equal to 

(A) – γ^(1/2) {(ΔV) / V} 

(B) – γ {(ΔV) / V} 

(C) – γ²{(ΔV) / V} 

(D) – (ΔV / V)

Answer 1

Correct option: (D) γ – {(ΔV) / V}

Explanation:

Isothermal expansion means T is constant

As PV = n ∙ R ∙ T

Hence PV = constant

∴ P ΔV – V ΔP = 0

(ΔP / P) = – (ΔV / V)