Question

When 1g of waters O°c and 10⁵(N /m²) Pressure is Converted into ice of Volume 1.091 cm³ the external work done be .......... J. 

(A) 0.0182 

(B) – 0.0091 

(C) – 0.0182 

(D) 0.0091

Answer 1

Correct option: (D) 0.0091

Explanation:

W = P ∙ ΔV

Given P = 10⁵ N/m² 

1 gm water occupies 1 cm³ volume

i.e.      V₁ = 1cm³ = (10^–2)³ = 10^–6 m³ 

V² = 1.091 cm³ = 1.091 × 10^–6 m³ 

∴   W = P ∙ ΔV

= 10⁵ × (1.091 – 1)10^–6 

= 10^–1 × 0.091

= 0.0091 J