The correct option (b) [ex/(1 + x2)]
Explanation:
ex[(1 – x)/(1 + x2)]2 = ex[(1 – 2x + x2)/(1 + x2)2]
= ex[{(1 + x2) – 2x}/(1 + x2)2]
= ex[{1/(1 + x2)}/{(2x)/(1 + x2)2}]
This is of the form ex [f(x) + f'(x)]
whose solution is given by exf(x) + c
∴ I = ex ∙ [1/(1 + x2)] + c
∴ I = [ex/(1 + x2)] + c