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in Mathematics by (75.3k points)

∫ex[(1 – x)/(1 + x2)]2dx = __________ + c 

(a) ex(1 + x2

(b) [ex/(1 + x2)] 

(c) ex[(1 – x)/(1 + x2)] 

(d) ex(1 – x2)

1 Answer

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by (70.6k points)
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Best answer

The correct option (b) [ex/(1 + x2)] 

Explanation:

ex[(1 – x)/(1 + x2)]2 = ex[(1 – 2x + x2)/(1 + x2)2

= ex[{(1 + x2) – 2x}/(1 + x2)2

= ex[{1/(1 + x2)}/{(2x)/(1 + x2)2}] 

This is of the form ex [f(x) + f'(x)] 

whose solution is given by exf(x) + c 

∴ I = ex ∙ [1/(1 + x2)] + c 

∴ I = [ex/(1 + x2)] + c

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