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An electron tube was sealed off during manufacture at a pressure of 1 × 10–7 torr at 27°C. Its volume is 100 cm3. The number of molecules that remain in the tube is­­­­­_______(density of mercury is 13.6 gcm–3) (1 torr = 133 Pa) 

(A) 3.9 × 1011 

(B) 3 × 1016 

(C) 2 × 1014 

(D) 7 × 1011

1 Answer

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Best answer

Correct option: (A) 3.9 × 1011

Explanation:

Given: P = 1.2 × 10–7 torr = 1.2 × 10–7 × 133 -------- as 1 torr = 133 Pa

= 159.6 × 10–7 Pa = 159.6 × 10–7 N/m2 

V = 100 cm3 = 100 × 10–6 m3 

T = 27°C = 300 k

As PV = NKBT

∴ N = No of molecules = {(PV) / (KBT)}

= {(159.6 × 10–7 × 100 × 10–6) / (1.38 × 10–23 × 300)}

= 0.385 × 10+12 

= 3.85 × 1011

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