Question

The experiment, using a resonance tube set–up, was carried out in a room at a temperature θ°C . The tuning fork used had a frequency N(Hz) and the first and second positions of resonance were observed for lengths l₁ (cm) and l₂ (cm), respectively, of the air–column. From these observations, one can say that the velocity of sound, in air, at 0°C, equals

(1) \(\frac{N(l_2-l_1)}{50}(1+\frac{\theta}{273})^{1/2} (m/s)\)

(2) \(\frac{N(l_2-l_1)}{50}(1+\frac{\theta}{273})^{-1/2} (m/s)\)

(3) \(\frac{N(l_2-l_1)}{50}(1-\frac{\theta}{273})^{-1/2} (m/s)\)

(4) \(\frac{N(l_2+l_1)}{50}(1+\frac{\theta}{273})^{-1/2} (m/s)\)

Answer 1

 (2) \(\frac{N(l_2-l_1)}{50}(1+\frac{\theta}{273})^{-1/2} (m/s)\)

We also have