Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
183 views
in Physics by (55.3k points)
closed by

Three layers of three different transparent media (of refractive indices n1 , n2 and n3 , respectively) have thicknesses d1 , d2 and d3 , respectively. Their total apparent depth, when viewed from above, would appear to be (nearly)

(1) \(\frac{d_1}{n_2}+\frac{d_2}{n_3}+\frac{d_3}{n_1}\)

(2) \(\frac{d_1}{n_2}-\frac{d_2}{n_3}-\frac{d_3}{n_1}\)

(3) \(\frac{1}{n_1n_2n_3}\) (d1n2n3+d2n3n1+d3n1n2)

(4) \(\frac{1}{n_1n_2n_3}\)  (d1n1n2+d2n2n3+d3n3n1)

1 Answer

+1 vote
by (55.9k points)
selected by
 
Best answer

(3) \(\frac{1}{n_1n_2n_3}\) (d1n2n3+d2n3n1+d3n1n2)

The apparent depth, of a layer of a medium of refractive index μ, is (1/μ) times its real depth. Hence the total apparent depth, of the three layers, would be

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...