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If ∆ABC and ∆DEF are similar and AB = 1.2 cm, DE = 1.4 cm then the ratio of areas of ∆ABC and ∆DEF is

(A) 16:25

(B) 49:81

(C) 36:49

(D) 9:16

1 Answer

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Best answer

Correct option is (C) 36:49

\(\frac{Area(\triangle ABC)}{Area (\triangle DEF)} = \left(\frac{AB}{DE}\right)^2 \)

\(= \left(\frac{1.2}{1.4}\right)^2\)

\(= \left(\frac{12}{14}\right)^2\)

\(= \frac{6^2}{7^2}\)

\(= \frac{36}{49}\)

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