Radius of curvature

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ASPECT · Answer 1 · 2023-01-08T16:15:32+0000

I hope you find your answer in the given link

AnjaliJangir · Answer 2 · 2023-01-09T04:12:32+0000

To find the radius of curvature of the curve

\(y = 4\sin x-\sin2x\)

at point \(x = \pi/2\)

Step 1: find y'

\(\frac{dy}{dx} = y' = 4\cos x - 2\cos2x\)

Step 2: find y"

\(\frac{d^2y}{dx^2} = y'' = -4\sin x+4\sin2x\)

Step 3: Apply the formula