Correct option is (c) 9.26
40 ml of 0.1M NH3 solution
= 40 x 0.1 milli = 4 millimol
20 ml of 0.1 M HCl = 20 x 0.1 = 2 millimol
2 millimol of HCl neutralise 2 millimol of NH4OH, to form 2 millimol of NH4OH.
NH4OH left = 2 millimol
Total volume = 60 ml
